F(x)=2x^2-5+6

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Solution for F(x)=2x^2-5+6 equation: 



(F)=2F^2-5+6

We move all terms to the left:

(F)-(2F^2-5+6)=0

We get rid of parentheses

-2F^2+F+5-6=0

We add all the numbers together, and all the variables

-2F^2+F-1=0

a = -2; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-2)·(-1)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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